The ratio of intensities at two points $P$ and $Q$ on the screen in a Young's double-slit experiment,where the phase differences between two waves of the same amplitude are $\pi / 3$ and $\pi / 2$ respectively,is:

In the Young's double slit experiment,if the phase difference between the two waves interfering at a point is $\phi$,the intensity at that point can be expressed by the expression:

In Young's double slit experiment,a mica sheet of thickness $t$ and refractive index $\mu$ is introduced in the path of the ray from the first source $S_1$. By what distance will the fringe pattern be displaced?

In Young's double slit experiment,the intensity at a point where the path difference is $\frac{\lambda}{6}$ is $I$. If $I_0$ denotes the maximum intensity,find the ratio $\frac{I}{I_0}$.

Two slits separated by $4\, mm$ are illuminated by light of wavelength $6000\,\mathring{A}$. What will be the fringe width on a screen placed $2\, m$ away from the slits? (in $mm$)

In Young's double slit experiment, the distance between the slits is $3 \text{ mm}$ and the slits are $2 \text{ m}$ away from the screen. Two interference patterns can be obtained on the screen due to light of wavelength $480 \text{ nm}$ and $600 \text{ nm}$ respectively. The separation on the screen between the $5^{th}$ order bright fringes of the two interference patterns is