The ratio of minimum wavelengths of Lyman and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The minimum wavelength of a spectral series corresponds to the transition from $n_{i}=\infty$ to the final orbit $n_{f}$.For the Lyman series,$n_{

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(B) The minimum wavelength of a spectral series corresponds to the transition from $n_{i}=\infty$ to the final orbit $n_{f}$.For the Lyman series,$n_{f}=1$:$\frac{1}{(\lambda_{\min})_{L}} = R \left[ \frac{1}{1^2} - \frac{1}{\infty^2} \right] = R$$\Rightarrow (\lambda_{\min})_{L} = \frac{1}{R}$  --- $(i)$For the Balmer series,$n_{f}=2$:$\frac{1}{(\lambda_{\min})_{B}} = R \left[ \frac{1}{2^2} - \frac{1}{\infty^2} \right] = \frac{R}{4}$$\Rightarrow (\lambda_{\min})_{B} = \frac{4}{R}$  --- (ii)Dividing equation $(i)$ by (ii):$\frac{(\lambda_{\min})_{L}}{(\lambda_{\min})_{B}} = \frac{1/R}{4/R} = \frac{1}{4} = 0.25$

The ratio of minimum wavelengths of Lyman and Balmer series will be

Similar Questions

The number of values of $x$ in the interval $[0, 5\pi]$ satisfying the equation $3\sin^2x - 7\sin x + 2 = 0$ is

Under the influence of a uniform magnetic field,a charged particle is moving in a circle of radius $R$ with constant speed $v$. The time period of the motion

Which of the following is the order of maize?

Which of the following isomerism is not possible for complexes having molecular formulae?
$(I) Pt(SCN)_2 \cdot 3PEt_3$,$(II) CoBr \cdot SO_4 \cdot 5NH_3$,$(III) FeCl_2 \cdot 6H_2O$

Vedclass Test Series

Exam Paper Generator

Online Exam Module