The ratio of specific heat at constant pressure to specific heat at constant volume $(\gamma)$ for a gas is given by $\gamma = 1 + \frac{2}{f}$,where $f$ is the number of degrees of freedom of a molecule of the gas. What is the ratio of $\gamma_{d}$ for a rigid diatomic gas to $\gamma_{m}$ for a monoatomic gas?
- A$\frac{14}{23}$
- B$\frac{25}{21}$
- C$\frac{21}{25}$
- D$\frac{23}{14}$
Explore More
Similar Questions
If the degrees of freedom of a gas molecule is $6$,then the total internal energy of the gas molecule at a temperature of $47^{\circ} C$ (in $eV$) is (Boltzmann constant $= 1.38 \times 10^{-23} \ J \ K^{-1}$)
The number of rotational degrees of freedom of a diatomic molecule is:
How many degrees of freedom does a diatomic gas have due to its translational motion?
Medium
View SolutionIf $\gamma$ is the ratio of specific heats of an ideal gas,the number of degrees of freedom of the gas molecules is .......
Easy
View SolutionIf the internal energy of $3$ moles of a gas at a temperature of $27^{\circ} C$ is $2250 R$,then the number of degrees of freedom of the gas is (where $R$ is the universal gas constant).
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo