The ratio of spin-only magnetic moment values | vedclass

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(D) For $[Cr(CN)_6]^{3-}$,the oxidation state of $Cr$ is $+3$. The electronic configuration is $3d^3$. Since $CN^-$ is a strong field ligand,the confi

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(D) For $[Cr(CN)_6]^{3-}$,the oxidation state of $Cr$ is $+3$. The electronic configuration is $3d^3$. Since $CN^-$ is a strong field ligand,the configuration is $t_{2g}^3 e_g^0$. The number of unpaired electrons $n = 3$.$\mu_1 = \sqrt{n(n+2)} = \sqrt{3(3+2)} = \sqrt{15} \ BM$.For $[Cr(H_2O)_6]^{3+}$,the oxidation state of $Cr$ is $+3$. The electronic configuration is $3d^3$. Since $H_2O$ is a weak field ligand,the configuration is $t_{2g}^3 e_g^0$. The number of unpaired electrons $n = 3$.$\mu_2 = \sqrt{n(n+2)} = \sqrt{3(3+2)} = \sqrt{15} \ BM$.The ratio $\frac{\mu_1}{\mu_2} = \frac{\sqrt{15}}{\sqrt{15}} = 1$.

The ratio of spin-only magnetic moment values $\mu_{eff}[Cr(CN)_6]^{3-} / \mu_{eff}[Cr(H_2O)_6]^{3+}$ is $.........$.

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