Number of stereoisomers possible for the octa | vedclass

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(D) For the complex $[Co(NH_3)_3Cl_3]$,it exists in two geometric isomeric forms: $fac$ (facial) and $mer$ (meridional). Both are optically inactive,s

Vedclass · Accepted Answer

$2$ and $3$

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(D) For the complex $[Co(NH_3)_3Cl_3]$,it exists in two geometric isomeric forms: $fac$ (facial) and $mer$ (meridional). Both are optically inactive,so there are $2$ stereoisomers.For the complex $[Ni(en)_2Cl_2]$,it exists in $trans$ and $cis$ forms. The $trans$ form is achiral,while the $cis$ form exists as a pair of enantiomers. Thus,there are $3$ stereoisomers in total ($1$ trans + $2$ cis enantiomers).

Complexes	No. of unpaired electrons
$A. [CrF_6]^{4-}$	$P. 5$
$B. [MnF_6]^{4-}$	$Q. 2$
$C. [Cr(CN)_6]^{4-}$	$R. 1$
$D. [Mn(CN)_6]^{4-}$	$S. 4$

Number of stereoisomers possible for the octahedral complexes $[Co(NH_3)_3Cl_3]$ and $[Ni(en)_2Cl_2]$,respectively,are (where $en = 1,2-$ethylenediamine):

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Which of the following coordination compounds would exhibit optical isomerism?

The correct match is:

Complexes No. of unpaired electrons

$A. [CrF_6]^{4-}$ $P. 5$

$B. [MnF_6]^{4-}$ $Q. 2$

$C. [Cr(CN)_6]^{4-}$ $R. 1$

$D. [Mn(CN)_6]^{4-}$ $S. 4$

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