Which compound has a magnetic moment equal to | vedclass

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(C) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.For $\mu = 4.90 \ B.M.$,we

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$FeSO_4$

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(C) The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.For $\mu = 4.90 \ B.M.$,we solve $\sqrt{n(n+2)} = 4.90$,which gives $n = 4$.In $FeSO_4$,the iron ion is $Fe^{2+}$.The electronic configuration of $Fe^{2+}$ is $[Ar] 3d^6$.In the $3d^6$ configuration,there are $4$ unpaired electrons.Therefore,$FeSO_4$ has a magnetic moment of $4.90 \ B.M.$

Which compound has a magnetic moment equal to $4.90 \ B.M.$?

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