The ratio of the average translational kineti | vedclass

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Question

(C) The average translational kinetic energy $(K_{avg})$ of a gas molecule is given by the formula: $K_{avg} = \frac{3}{2} k_B T$, where $k_B$ is the

Vedclass · Accepted Answer

$1: 1$

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(C) The average translational kinetic energy $(K_{avg})$ of a gas molecule is given by the formula: $K_{avg} = \frac{3}{2} k_B T$, where $k_B$ is the Boltzmann constant and $T$ is the absolute temperature.Since the temperature $T$ is the same for both hydrogen and oxygen, the average translational kinetic energy depends only on the temperature.Therefore, the ratio of the average translational kinetic energies of hydrogen and oxygen is $1: 1$.

The ratio of the average translational kinetic energies of hydrogen and oxygen at the same temperature is

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