The translational kinetic energy of the molec | vedclass

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(B) The translational kinetic energy of a gas molecule is given by the formula $E = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the

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increasing $T$ to $2T$

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(B) The translational kinetic energy of a gas molecule is given by the formula $E = \frac{3}{2}kT$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature.From this relation,it is clear that the kinetic energy $E$ is directly proportional to the absolute temperature $T$ $(E \propto T)$.To double the kinetic energy $(E' = 2E)$,we must double the absolute temperature $(T' = 2T)$.Therefore,the temperature must be increased to $2T$.

The translational kinetic energy of the molecules of a gas at absolute temperature $T$ can be doubled by:

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