The ratio of the de-Broglie wavelengths for t | vedclass

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(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass,and $v$ is the

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$m_p : m_e$

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(A) The de-Broglie wavelength $\lambda$ is given by the formula $\lambda = \frac{h}{mv}$,where $h$ is Planck's constant,$m$ is the mass,and $v$ is the velocity of the particle.Since both the electron and the proton are moving with the same velocity $v$,the wavelength is inversely proportional to the mass of the particle: $\lambda \propto \frac{1}{m}$.Therefore,the ratio of the de-Broglie wavelength of the electron $(\lambda_e)$ to that of the proton $(\lambda_p)$ is given by $\frac{\lambda_e}{\lambda_p} = \frac{m_p}{m_e}$.Thus,the ratio is $m_p : m_e$.

The ratio of the de-Broglie wavelengths for the electron and proton moving with the same velocity is ($m_p$ = mass of proton,$m_e$ = mass of electron).

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