The ratio of the energy of a photon with lamb | vedclass

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is

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$2$

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(A) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$,where $h$ is Planck's constant,$c$ is the speed of light,and $\lambda$ is the wavelength.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional to the wavelength $\lambda$,i.e.,$E \propto \frac{1}{\lambda}$.Let $E_1$ be the energy of the photon with $\lambda_1 = 150\,nm$ and $E_2$ be the energy of the photon with $\lambda_2 = 300\,nm$.Then,the ratio is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Substituting the given values: $\frac{E_1}{E_2} = \frac{300\,nm}{150\,nm} = 2$.Therefore,the ratio is $2:1$.

The ratio of the energy of a photon with $\lambda = 150\,nm$ to that with $\lambda = 300\,nm$ is

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