The ratio of the magnitudes of the electric field to the magnetic field of an electromagnetic wave is of the order of

How are microwaves produced?

The electric field of a plane electromagnetic wave of amplitude $2 \, V/m$ varies with time,propagating along the $z$-axis. The average energy density of the magnetic field (in $J/m^3$) is:

The electric field and magnetic field components of an electromagnetic wave going through vacuum are described by
$E_x = E_0 \sin(kz - \omega t)$
$B_y = B_0 \sin(kz - \omega t)$
Then the correct relation between $E_0$ and $B_0$ is given by

$A$ plane electromagnetic $(EM)$ wave is propagating along the $x$-direction. It has a wavelength of $4 \text{ mm}$. If the electric field is in the $y$-direction with a maximum magnitude of $60 \text{ Vm}^{-1}$,the equation for the magnetic field is:

Atmospheric conditions affect ......... space waves.