The ratio of the rate of diffusion of SO_2 to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas

Vedclass · Accepted Answer

$1: 2$

Vedclass · Answer

(B) According to Graham's Law of diffusion,the rate of diffusion $(r)$ is inversely proportional to the square root of the molar mass $(M)$ of the gas: $r \propto \frac{1}{\sqrt{M}}$.The molar mass of $SO_2$ is $32 + (16 	imes 2) = 64 \ g/mol$.The molar mass of $CH_4$ is $12 + (1 	imes 4) = 16 \ g/mol$.Therefore,the ratio of the rate of diffusion of $SO_2$ to $CH_4$ is:$\frac{r_{SO_2}}{r_{CH_4}} = \sqrt{\frac{M_{CH_4}}{M_{SO_2}}} = \sqrt{\frac{16}{64}} = \sqrt{\frac{1}{4}} = \frac{1}{2}$.Thus,the ratio is $1: 2$.

The ratio of the rate of diffusion of $SO_2$ to $CH_4$ is

Similar Questions

$50 \ mL$ of hydrogen diffuses out through a small hole from a vessel in $20 \ min$. The time needed for $40 \ mL$ of oxygen to diffuse out is ............. $min$.

$A$ gaseous mixture contains equal masses of dihydrogen gas,dioxygen gas and methane gas at a total pressure of $380 \ torr$. The partial pressure of methane gas is ........... $torr$.

When the temperature increases,the surface tension of water $......$

$A$ closed container contains a mixture of non-reacting gases $A$ and $B$. The partial pressures of $A$ and $B$ are $4.5 \ bar$ and $5.5 \ bar$ respectively. Find the mole fractions of $A$ and $B$ respectively.

Which of the following gases is not easily soluble in water?

Vedclass Test Series

Exam Paper Generator

Online Exam Module