The reaction CH_2 = CH - CH_3 + HBr rightarro | vedclass

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(B) In this reaction,$HBr$ undergoes heterolytic fission to produce an electrophile $H^{+}$:$HBr \rightarrow H^{+} + Br^{-}$The electrophile $H^{+}$ a

Vedclass · Accepted Answer

Electrophilic addition

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(B) In this reaction,$HBr$ undergoes heterolytic fission to produce an electrophile $H^{+}$:$HBr \rightarrow H^{+} + Br^{-}$The electrophile $H^{+}$ attacks the double bond of propene to form a stable carbocation intermediate $(CH_3-\stackrel{+}{C}H - CH_3)$.Subsequently,the nucleophile $Br^{-}$ attacks the carbocation to form $2$-bromopropane.Since the initial step involves the attack of an electrophile on the alkene,this is an electrophilic addition reaction.

The reaction $CH_2 = CH - CH_3 + HBr \rightarrow CH_3CHBr - CH_3$ is

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