The reaction for the formation of NaCl is: | vedclass

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Question

(B) The standard enthalpy of formation is defined as the change in enthalpy when $1 	ext{ mole}$ of a compound is formed from its constituent element

Vedclass · Accepted Answer

$Na_{(s)} + \frac{1}{2} Cl_{2(g)} \longrightarrow NaCl_{(s)}$

Vedclass · Answer

(B) The standard enthalpy of formation is defined as the change in enthalpy when $1 	ext{ mole}$ of a compound is formed from its constituent elements in their most stable physical states at $298 	ext{ K}$ and $1 	ext{ bar}$ pressure.Sodium $(Na)$ exists as a solid $(s)$ at room temperature,and chlorine $(Cl_2)$ exists as a gas $(g)$.Therefore,the correct reaction is: $Na_{(s)} + \frac{1}{2} Cl_{2(g)} \longrightarrow NaCl_{(s)}$.

The reaction for the formation of $NaCl$ is:

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