The reaction of 1-bromohexane with aqueous Na | vedclass

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(C) The reaction of $1$-bromohexane with aqueous $NaOH$ is a nucleophilic substitution reaction. Since $1$-bromohexane is a primary alkyl halide,the r

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second order kinetics

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(C) The reaction of $1$-bromohexane with aqueous $NaOH$ is a nucleophilic substitution reaction. Since $1$-bromohexane is a primary alkyl halide,the reaction proceeds via the $S_N2$ mechanism. In an $S_N2$ mechanism,the rate of reaction depends on the concentration of both the substrate ($1$-bromohexane) and the nucleophile $(OH^-)$. Therefore,the rate law is $Rate = k[CH_3(CH_2)_5Br][OH^-]$. This indicates that the reaction follows second order kinetics.

The reaction of $1$-bromohexane with aqueous $NaOH$ solution follows the order

Similar Questions

Determine the number of chiral products (including stereoisomers) formed upon $E_2$ elimination of the given substrate with $alc. KOH$.

Which of the following is an incorrect statement?

Increasing the concentration of an electrophile (substrate) in a typical $S_N2$ reaction by a factor of $3$ and the concentration of the nucleophile by a factor of $3$ will change the reaction rate to

The relative reactivity of the following halides toward $S_{N}2$ reaction follows the order:
$(P)$ $CH_2=CH-Cl$
$(Q)$ $CH_3-CH_2-Cl$
$(R)$ $CH_3-O-CH_2-CH_2-Cl$
$(S)$ $C_6H_5-CH_2-Cl$

Consider the above chemical reaction. Product $A$ is:

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