The refracting angle of a prism is $A$ and the refractive index of the material of the prism is $\cot \frac{A}{2}$. The angle of minimum deviation is:

$A$ prism of refractive index $\sqrt{2}$ has a refracting angle of $60^{\circ}$. At what angle must a ray be incident on it so that it suffers minimum deviation (in $^{\circ}$)?

By placing the prism in the minimum deviation position,the images of the spectrum:

$A$ parallel beam of monochromatic light is incident at one surface of an equilateral prism. The angle of incidence is $55^o$ and the angle of emergence is $46^o$. The angle of minimum deviation will be:

$A$ thin prism of angle $6^{\circ}$ and refractive index for yellow light $(n_{Y}) = 1.5$ is combined with another prism of angle $5^{\circ}$ and $n_{Y} = 1.55$. The combination produces no dispersion. The net average deviation $(\delta)$ produced by the combination is $(\frac{1}{x})^{\circ}$. The value of $x$ is.......

$A$ ray of light suffers minimum deviation when incident on a prism having an angle of the prism equal to $60^{\circ}$. The refractive index of the prism material is $\sqrt{2}$. The angle of incidence (in degrees) is . . . . . . .