The region in the output voltage versus input voltage graph where a transistor can be used as an amplifier is

The current amplification factor of a transistor is $50$. The input resistance when used in common emitter mode is $1 \text{ k}\Omega$. The peak value of the collector current for an a.c. input voltage of $0.01 \text{ V}$ peak is:

In a transistor,if the collector current is $98 \%$ of emitter current,then the ratio of the base and collector currents is

$A$ common emitter amplifier is designed with an $NPN$ transistor $(\alpha = 0.99)$. The input impedance is $1 \ k\Omega$ and the load resistance is $10 \ k\Omega$. The voltage gain will be:

The current amplification factor of a transistor in common emitter configuration is $80$. If the emitter current is $2.43 \text{ mA}$, then the base current is (in $\mu \text{A}$)

In a transistor amplifier,$\beta = 62$,$R_L = 5000\, \Omega$,and the internal resistance of the transistor is $R_i = 500\, \Omega$. The voltage amplification of the amplifier will be: