The relation between volume (V) and absolute | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings $(dQ = 0)$.For an id

Vedclass · Accepted Answer

$TV^{\gamma-1} = 	ext{constant}$

Vedclass · Answer

(D) An adiabatic process is a thermodynamic process in which there is no exchange of heat between the system and its surroundings $(dQ = 0)$.For an ideal gas undergoing a reversible adiabatic process,the relationship between pressure $(P)$ and volume $(V)$ is given by $PV^{\gamma} = 	ext{constant}$,where $\gamma$ is the adiabatic index (ratio of specific heats $C_p/C_v$).Using the ideal gas law $PV = nRT$,we can express pressure as $P = \frac{nRT}{V}$.Substituting this into the adiabatic equation: $(\frac{nRT}{V})V^{\gamma} = 	ext{constant}$.Since $nR$ is a constant,we get $T V^{\gamma-1} = 	ext{constant}$.

The relation between volume $(V)$ and absolute temperature $(T)$ of a gas in an adiabatic process is

Similar Questions

The relation between absolute temperature $(T)$ and pressure $(P)$ of a gas in an adiabatic process is

In adiabatic compression, the decrease in volume is associated with

Which of the following is true in the case of an adiabatic process, where $\gamma = C_p / C_V$?

$A$ gas at $37^{\circ} C$ is compressed adiabatically to half of its volume. What is the final temperature of the gas (in $^{\circ} C$)? (Ratio of specific heat capacities of the gas is $1.5$)

During the adiabatic expansion of $2 \, moles$ of a gas,the internal energy was found to have decreased by $100 \, J$. The work done by the gas in this process is ..... $J$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module