The resultant of vec{A} and vec{B} makes an a | vedclass

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(C) Let the resultant vector be $\vec{R} = \vec{A} + \vec{B}$.From the triangle law of vector addition,the angle $\alpha$ between $\vec{R}$ and $\vec{

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$\alpha  B$

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(C) Let the resultant vector be $\vec{R} = \vec{A} + \vec{B}$.From the triangle law of vector addition,the angle $\alpha$ between $\vec{R}$ and $\vec{A}$ is given by $	an \alpha = \frac{B \sin 	heta}{A + B \cos 	heta}$,where $	heta$ is the angle between $\vec{A}$ and $\vec{B}$.Similarly,the angle $\beta$ between $\vec{R}$ and $\vec{B}$ is given by $	an \beta = \frac{A \sin 	heta}{B + A \cos 	heta}$.Geometrically,the resultant vector $\vec{R}$ is always closer to the vector with the larger magnitude.If $A > B$,then the resultant $\vec{R}$ will be closer to $\vec{A}$,which means the angle $\alpha$ will be smaller than the angle $\beta$ (i.e.,$\alpha Conversely,if $A  \beta$.Therefore,$\alpha  B$.

The resultant of $\vec{A}$ and $\vec{B}$ makes an angle $\alpha$ with $\vec{A}$ and $\beta$ with $\vec{B}$. Which of the following is correct?

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