The shortest wavelength of $He^{+}$ ion in Balmer series is $x$. Then,the longest wavelength in the Paschen series of $Li^{2+}$ is:

  • A
    $\frac{36x}{5}$
  • B
    $\frac{16x}{7}$
  • C
    $\frac{9x}{5}$
  • D
    $\frac{5x}{9}$

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