The simplification of left[frac{1}{2}+frac{1} | vedclass

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Question

(B) To simplify the expression $\left[\frac{1}{2}+\frac{1}{2}\left\{\frac{3}{4}-\frac{1}{2}\left(\frac{7}{8}-\frac{3}{4}\right)\right\}\right]$,we fol

Vedclass · Accepted Answer

$\frac{27}{32}$

Vedclass · Answer

(B) To simplify the expression $\left[\frac{1}{2}+\frac{1}{2}\left\{\frac{3}{4}-\frac{1}{2}\left(\frac{7}{8}-\frac{3}{4}ight)ight\}ight]$,we follow the $BODMAS$ rule.Step $1$: Solve the innermost bracket (parentheses): $\left(\frac{7}{8}-\frac{3}{4}ight) = \left(\frac{7-6}{8}ight) = \frac{1}{8}$.Step $2$: Solve the curly bracket: $\left\{\frac{3}{4}-\frac{1}{2} 	imes \frac{1}{8}ight\} = \left\{\frac{3}{4}-\frac{1}{16}ight\} = \left\{\frac{12-1}{16}ight\} = \frac{11}{16}$.Step $3$: Solve the square bracket: $\left[\frac{1}{2}+\frac{1}{2} 	imes \frac{11}{16}ight] = \left[\frac{1}{2}+\frac{11}{32}ight] = \left[\frac{16+11}{32}ight] = \frac{27}{32}$.

The simplification of $\left[\frac{1}{2}+\frac{1}{2}\left\{\frac{3}{4}-\frac{1}{2}\left(\frac{7}{8}-\frac{3}{4}\right)\right\}\right]$ yields

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