The size of the species $Pb$,$Pb^{2+}$,and $Pb^{4+}$ decreases as:

  • A
    $Pb^{4+} > Pb^{2+} > Pb$
  • B
    $Pb > Pb^{2+} > Pb^{4+}$
  • C
    $Pb > Pb^{4+} > Pb^{2+}$
  • D
    $Pb^{4+} > Pb > Pb^{2+}$

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Similar Questions

The correct increasing order of the ionic radii is:

The statement$(s)$ that are correct about the species $O^{2-}$,$F^{-}$,$Na^{+}$,and $Mg^{2+}$.
$(A)$ All are isoelectronic
$(B)$ All have the same nuclear charge
$(C)$ $O^{2-}$ has the largest ionic radii
$(D)$ $Mg^{2+}$ has the smallest ionic radii
Choose the most appropriate answer from the options given below :

Observe the following data.
IonRadius $(pm)$
$Q^{a+}$$53$
$X^{b+}$$66$
$Y^{c+}$$40$
$Z^{d+}$$100$
$Q^{a+}, X^{b+}, Y^{c+}, Z^{d+}$ are respectively

The correct order of increasing atomic radius of the following elements is

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Assertion $(A)$: The ionic radii of $Na^{+}$ and $F^{-}$ are same.
Reason $(R)$: Both $Na^{+}$ and $F^{-}$ are isoelectronic species.
The correct answer is:

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