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(B) The slope of the anode characteristic curve is given by $\frac{1}{r_p}$,where $r_p$ is the plate resistance.Given $\frac{1}{r_p} = 0.02 \, mA/V =

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$50$

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(B) The slope of the anode characteristic curve is given by $\frac{1}{r_p}$,where $r_p$ is the plate resistance.Given $\frac{1}{r_p} = 0.02 \, mA/V = 0.02 	imes 10^{-3} \, A/V$.Therefore,$r_p = \frac{1}{0.02 	imes 10^{-3}} \, \Omega = 50 	imes 10^3 \, \Omega = 50 \, k\Omega$.The slope of the mutual characteristic curve is the transconductance $g_m$.Given $g_m = 1 \, mA/V = 1 	imes 10^{-3} \, A/V$.The amplification factor $\mu$ is defined as $\mu = r_p 	imes g_m$.Substituting the values: $\mu = (50 	imes 10^3 \, \Omega) 	imes (1 	imes 10^{-3} \, A/V) = 50$.Thus,the amplification factor is $50$.

The slopes of the anode and mutual characteristics of a triode are $0.02 \, mA/V$ and $1 \, mA/V$ respectively. What is the amplification factor of the valve?

Similar Questions

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