The smallest positive number divisible by 24, | vedclass

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(C) To find the smallest positive number divisible by $24, 36$,and $48$,we need to calculate the Least Common Multiple $(LCM)$ of these numbers.Step $

Vedclass · Accepted Answer

$144$

Vedclass · Answer

(C) To find the smallest positive number divisible by $24, 36$,and $48$,we need to calculate the Least Common Multiple $(LCM)$ of these numbers.Step $1$: Find the prime factorization of each number:$24 = 2^3 	imes 3^1$$36 = 2^2 	imes 3^2$$48 = 2^4 	imes 3^1$Step $2$: The $LCM$ is the product of the highest power of each prime factor present in the numbers:$LCM = 2^4 	imes 3^2$$LCM = 16 	imes 9 = 144$Therefore,the required smallest number is $144$.

The smallest positive number divisible by $24, 36$,and $48$ is $\ldots \ldots \ldots \ldots .$

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