The solubility of $AgBr$ is $7.1 \times 10^{-7} \ mol \ dm^{-3}$. Calculate its solubility product at the same temperature.
- A$5.04 \times 10^{-13}$
- B$3.67 \times 10^{-13}$
- C$5.89 \times 10^{-13}$
- D$7.08 \times 10^{-13}$
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