The species A,B,C,D formed in the following b | vedclass

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Question

(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electro

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$CH_3CH_2^{+}, I^{-}, CH_3CH_2^{-}, Cu^{+}$

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(A) In the first reaction,$CH_3CH_2-I \rightarrow A + B$,the bond breaks heterolytically such that the bonding electron pair moves to the more electronegative iodine atom. This results in the formation of an ethyl carbocation $(A = CH_3CH_2^{+})$ and an iodide ion $(B = I^{-})$.In the second reaction,$CH_3CH_2-Cu \rightarrow C + D$,the bond breaks heterolytically such that the bonding electron pair moves to the carbon atom because carbon is more electronegative than copper. This results in the formation of an ethyl carbanion $(C = CH_3CH_2^{-})$ and a copper cation $(D = Cu^{+})$.

The species $A$,$B$,$C$,$D$ formed in the following bond cleavages respectively are:

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Choose the correct answer from the options given below:

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