Which of the following species has no ppi - p | vedclass

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(A) The bond order of $O_2$ is $2.0$. $XeO_3$ has $sp^3$ hybridization with one lone pair and three $Xe=O$ bonds. It contains $p\pi - d\pi$ bonding. $

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$XeO_3$

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(A) The bond order of $O_2$ is $2.0$. $XeO_3$ has $sp^3$ hybridization with one lone pair and three $Xe=O$ bonds. It contains $p\pi - d\pi$ bonding. $ClO_3^-$ has $sp^3$ hybridization with one lone pair and three $Cl-O$ bonds,involving $p\pi - d\pi$ bonding. $PO_4^{3-}$ has $sp^3$ hybridization with four $P-O$ bonds,involving $p\pi - d\pi$ bonding. $SO_4^{2-}$ has $sp^3$ hybridization with four $S-O$ bonds. The bond order is calculated as $\frac{	ext{Total number of bonds}}{	ext{Total number of resonating structures}} = \frac{6}{4} = 1.5$. Wait,re-evaluating the question: The species $O_2$ has a bond order of $2$. Among the options,$XeO_3$ has $p\pi - d\pi$ bonds. $ClO_3^-$ has $p\pi - d\pi$ bonds. $PO_4^{3-}$ has $p\pi - d\pi$ bonds. $SO_4^{2-}$ has $p\pi - d\pi$ bonds. Actually,the species $O_2$ has a bond order of $2$. The question asks for a species with no $p\pi - p\pi$ bond. $XeO_3$ has $p\pi - d\pi$ bonds. $ClO_3^-$ has $p\pi - d\pi$ bonds. $PO_4^{3-}$ has $p\pi - d\pi$ bonds. $SO_4^{2-}$ has $p\pi - d\pi$ bonds. Considering the bond order of $O_2$ is $2$,the species $XeO_3$ has three $Xe=O$ bonds,effectively having a bond order of $2$ per $Xe-O$ linkage,and it lacks $p\pi - p\pi$ bonds because $Xe$ uses $d$-orbitals for $\pi$ bonding.

Which of the following species has no $p\pi - p\pi$ bond but has a bond order equal to that of $O_2$?

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