The statement $(p \wedge (\sim q))$ $\Rightarrow (p$ $\Rightarrow (\sim q))$ is

The logical statement $[\sim(\sim p \vee q) \vee (p \wedge r) \wedge (\sim q \wedge r)]$ is equivalent to

Which one of the following is a tautology?

$p$: If $7$ is an odd number,then $7$ is divisible by $2$.
$q$: If $7$ is a prime number,then $7$ is an odd number.
If $V_1$ and $V_2$ are the respective truth values of the contrapositive of $p$ and $q$,then $(V_1, V_2) \equiv$

$(p \wedge r) \Leftrightarrow (p \wedge (\sim q))$ is equivalent to $(\sim p)$ when $r$ is.

If $p$, $q$, $r$ are simple propositions with truth values $T$, $F$, $T$ respectively, then which of the following is not a true statement?