The statement pattern [(p vee q) wedge sim p] | vedclass

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a contradiction

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(A) To determine the nature of the statement pattern,we construct a truth table:| $p$ | $q$ | $\sim p$ | $\sim q$ | $p \vee q$ | $(p \vee q) \wedge \sim p$ | $[(p \vee q) \wedge \sim p] \wedge \sim q$ ||---|---|---|---|---|---|---|| $T$ | $T$ | $F$ | $F$ | $T$ | $F$ | $F$ || $T$ | $F$ | $F$ | $T$ | $T$ | $F$ | $F$ || $F$ | $T$ | $T$ | $F$ | $T$ | $T$ | $F$ || $F$ | $F$ | $T$ | $T$ | $F$ | $F$ | $F$ |Since all entries in the final column are $F$ (False),the statement pattern is a contradiction.

The statement pattern $[(p \vee q) \wedge \sim p] \wedge (\sim q)$ is

Similar Questions

If truth values of statements $p, q$ are true,and $r, s$ are false,then the truth values of the following statement patterns are respectively:
$a: \sim(p \wedge \sim r) \vee(\sim q \vee s)$
$b: (\sim q \wedge \sim r) \leftrightarrow(p \vee s)$
$c: (\sim p \vee q) \rightarrow(r \wedge \sim s)$

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The statement that is $TRUE$ among the following is:

Which of the following statement patterns is a contradiction?

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