The structure of XeF_{6} is experimentally de | vedclass

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(C) In $XeF_{6}$, the central atom $Xe$ has $8$ valence electrons.$6$ electrons are used in bonding with fluorine atoms (forming $6$ bond pairs), and

Vedclass · Accepted Answer

pentagonal bipyramid

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(C) In $XeF_{6}$, the central atom $Xe$ has $8$ valence electrons.$6$ electrons are used in bonding with fluorine atoms (forming $6$ bond pairs), and the remaining $2$ electrons form $1$ lone pair.Total electron pairs around $Xe = 6 	ext{ (bond pairs)} + 1 	ext{ (lone pair)} = 7$.According to $VSEPR$ theory, a steric number of $7$ corresponds to a pentagonal bipyramidal electron geometry.

List-$I$	List-$II$
$A. BrF_5$	$I. AB_4E$,see-saw
$B. SF_4$	$II. AB_4E_2$,square planar
$C. XeF_4$	$III. AB_5E$,square pyramidal
$D. ClF_3$	$IV. AB_3E_2$,$T$-shape

The structure of $XeF_{6}$ is experimentally determined to be a distorted octahedron. Its structure according to $VSEPR$ theory is

Similar Questions

Which of the following is the correct order of bond angles?

Which of the following is the incorrect order of bond angle?

The structure of $XeF_5^-$ is:

Which one of the following compounds has a bond angle of nearly $90^{\circ}$?

Match the following:

List-$I$ List-$II$

$A. BrF_5$ $I. AB_4E$,see-saw

$B. SF_4$ $II. AB_4E_2$,square planar

$C. XeF_4$ $III. AB_5E$,square pyramidal

$D. ClF_3$ $IV. AB_3E_2$,$T$-shape

The correct answer is:

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