The sum of all the real values of x satisfyin | vedclass

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(C) Given the equation $2^{(x - 1)(x^2 + 5x - 50)} = 1$.Since $2^0 = 1$,the exponent must be equal to $0$.Therefore,$(x - 1)(x^2 + 5x - 50) = 0$.Facto

Vedclass · Accepted Answer

$-4$

Vedclass · Answer

(C) Given the equation $2^{(x - 1)(x^2 + 5x - 50)} = 1$.Since $2^0 = 1$,the exponent must be equal to $0$.Therefore,$(x - 1)(x^2 + 5x - 50) = 0$.Factoring the quadratic expression $x^2 + 5x - 50$,we get $(x + 10)(x - 5) = 0$.So,the equation becomes $(x - 1)(x + 10)(x - 5) = 0$.The real values of $x$ are $x = 1, x = -10, x = 5$.The sum of these values is $1 + (-10) + 5 = -4$.

The sum of all the real values of $x$ satisfying the equation $2^{(x - 1)(x^2 + 5x - 50)} = 1$ is

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