The system of equations $2x + y - 5 = 0$,$x - 2y + 1 = 0$,and $2x - 14y - a = 0$ is consistent. Then,$a$ is equal to

The lines $ax + by + c = 0$,where $3a + 2b + 4c = 0$,are concurrent at the point:

The lines $x-2y+1=0$,$2x-3y-1=0$,and $3x-y+k=0$ are concurrent. The angle between the lines $3x-y+k=0$ and $mx-3y+6=0$ is $45^{\circ}$. If $m$ is an integer,then $m-k=$

The lines
$(p - q)x + (q - r)y + (r - p) = 0$
$(q - r)x + (r - p)y + (p - q) = 0$
$(r - p)x + (p - q)y + (q - r) = 0$ are

The equation of the line passing through the point of intersection of the lines $3x - y = 5$ and $x + 3y = 1$ and making equal intercepts on the axes is

If $3x + 6y + 2 = 0$,$x + y + 1 = 0$,and $2x - y + 3 = 0$ are three given lines,then the point $\left(\frac{-4}{3}, \frac{1}{3}\right)$ is