(D) The heat absorbed due to the Thomson effect is given by the formula: $H = \sigma q \Delta T$,where $\sigma$ is the Thomson coefficient,$q$ is the

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(D) The heat absorbed due to the Thomson effect is given by the formula: $H = \sigma q \Delta T$,where $\sigma$ is the Thomson coefficient,$q$ is the charge,and $\Delta T$ is the temperature difference.Given:$\sigma = 10 \mu V/K = 10 \times 10^{-6} \text{ } V/K$$q = 10 \text{ } C$$\Delta T = 60^{\circ}C - 50^{\circ}C = 10 \text{ } K$Substituting the values:$H = (10 \times 10^{-6} \text{ } V/K) \times (10 \text{ } C) \times (10 \text{ } K)$$H = 1000 \times 10^{-6} \text{ } J$$H = 10^{-3} \text{ } J = 1 \text{ } mJ$.

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The Thomson coefficient of a conductor is $10 \mu V/K$. The two ends of the conductor are maintained at $50^{\circ}C$ and $60^{\circ}C$,respectively. The amount of heat absorbed by the conductor when a charge of $10 C$ flows through it is:

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A
$1000 \text{ } J$
B
$100 \text{ } J$
C
$100 \text{ } mJ$
D
$1 \text{ } mJ$

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The Thomson coefficient of a conductor is $10 \mu V/K$. The two ends of the conductor are maintained at $50^{\circ}C$ and $60^{\circ}C$,respectively. The amount of heat absorbed by the conductor when a charge of $10 C$ flows through it is:

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