The three water-filled tanks shown have the same volume and height. If small identical holes are punched near their bottoms,which one will be the first to get empty?

In a cylindrical vessel containing liquid of density $\rho$,there are two holes in the side walls at heights of $h_1$ and $h_2$ respectively,such that the range of efflux at the bottom of the vessel is the same. The height of a hole,for which the range of efflux would be maximum,is:

$A$ cylinder contains water up to a height '$H$'. It has three orifices $O_1, O_2, O_3$ as shown in the figure. Let $V_1, V_2, V_3$ be the speed of efflux of water from the three orifices. Then

$A$ wide vessel with a small hole at the bottom is filled with two liquids. The density and height of one liquid are $\rho_1$ and $h_1$ and that of the other are $\rho_2$ and $h_2$ $(\rho_1 > \rho_2)$. The velocity of the liquid coming out of the hole is:

$A$ large tank filled with water to a height $h$ is to be emptied through a small hole at the bottom. The ratio of times taken for the level of water to fall from $h$ to $h/2$ and from $h/2$ to $0$ is

$A$ large tank is filled with water (density $= 10^3 \ kg/m^3$). $A$ small hole is made at a depth $10 \ m$ below the water surface. The range of water issuing out of the hole is $R$ on the ground. What extra pressure must be applied on the water surface so that the range becomes $2R$? (Take $1 \ atm = 10^5 \ Pa$ and $g = 10 \ m/s^2$)