The time period of a simple pendulum in a lif | vedclass

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Question

(D) When a lift descends with an acceleration $a$,the effective acceleration due to gravity $g_{eff}$ experienced by the pendulum is $g_{eff} = g - a$

Vedclass · Accepted Answer

Infinite

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(D) When a lift descends with an acceleration $a$,the effective acceleration due to gravity $g_{eff}$ experienced by the pendulum is $g_{eff} = g - a$.In this case,the lift is descending with an acceleration $a = g$.Therefore,the effective acceleration $g_{eff} = g - g = 0$.The time period of a simple pendulum is given by $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$.Substituting $g_{eff} = 0$,we get $T = 2\pi \sqrt{\frac{l}{0}} = \infty$.Thus,the time period becomes infinite.

The time period of a simple pendulum in a lift descending with constant acceleration $g$ is

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