The translational degrees of freedom (f_t) an | vedclass

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Question

(B) $CH_4$ molecule is a polyatomic non-linear molecule.For any molecule in three-dimensional space,the translational degrees of freedom $(f_t)$ are a

Vedclass · Accepted Answer

$f_t=3$ and $f_r=3$

Vedclass · Answer

(B) $CH_4$ molecule is a polyatomic non-linear molecule.For any molecule in three-dimensional space,the translational degrees of freedom $(f_t)$ are always $3$,corresponding to motion along the $x, y,$ and $z$ axes.For a non-linear polyatomic molecule,the rotational degrees of freedom $(f_r)$ are also $3$,corresponding to rotation about the three principal axes of inertia.Therefore,for $CH_4$,$f_t = 3$ and $f_r = 3$.

The translational degrees of freedom $(f_t)$ and rotational degrees of freedom $(f_r)$ of a $CH_4$ molecule are:

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