The types of hybridization present in 1, 2-bu | vedclass

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(A) The structure of $1, 2-$butadiene is $CH_2=C=CH-CH_3$. $1$. The first carbon atom $(CH_2=)$ is bonded to two hydrogens and one double bond,so it i

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$sp, sp^2, 	ext{ and } sp^3$

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(A) The structure of $1, 2-$butadiene is $CH_2=C=CH-CH_3$. $1$. The first carbon atom $(CH_2=)$ is bonded to two hydrogens and one double bond,so it is $sp^2$ hybridized. $2$. The second carbon atom $(=C=)$ is bonded to two double bonds,so it is $sp$ hybridized. $3$. The third carbon atom $(-CH-)$ is bonded to one hydrogen,one single bond,and one double bond,so it is $sp^2$ hybridized. $4$. The fourth carbon atom $(-CH_3)$ is bonded to three hydrogens and one single bond,so it is $sp^3$ hybridized. Thus,the types of hybridization present are $sp, sp^2, 	ext{ and } sp^3$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

The types of hybridization present in $1, 2-$butadiene are

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What is the number of $sp^3$ hybridized carbon atoms in $HO(CH_2)_2CH(CH_3)_2$?

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2 \ sp$ carbons
$B$. Ethylene $2$. $6 \ sp^2$ carbons
$C$. Acetylene $3$. $2 \ sp^3$ carbons
$D$. Benzene $4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

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