The unit of magnetic moment is . . . . . . .

  • A
    $A \cdot m^2$
  • B
    $A \cdot m^{-1}$
  • C
    $T \cdot J^{-1}$
  • D
    $J \cdot T^{-1}$

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$A$ rod of length $l$ having uniformly distributed charge $Q$ is rotated about one end with constant frequency $f$. Its magnetic moment is:

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Two circular concentric loops of radii $r_1 = 20\,cm$ and $r_2 = 30\,cm$ are placed in the $X, Y-$ plane as shown in the figure. $A$ current $I = 7\,A$ is flowing through them in opposite directions. The magnetic moment of this loop system is

$A$ loop carrying current $I$ lies in the $x$-$y$ plane as shown in the figure. The unit vector $\hat{k}$ is coming out of the plane of the paper. The magnetic moment of the current loop is:

Current $i$ is flowing in the rectangular loop placed in the $xyz$ plane as shown in the figure. Find the magnetic moment of the loop.

The ratio of the magnetic field at the centre of a current-carrying circular loop to its magnetic moment is '$x$'. When both the current and the radius are tripled, the new ratio will be:

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