(A) The given expression is of the form $\frac{a^{3}-b^{3}}{a^{2}+ab+b^{2}}$.We know the algebraic identity $a^{3}-b^{3} = (a-b)(a^{2}+ab+b^{2})$.Ther

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(A) The given expression is of the form $\frac{a^{3}-b^{3}}{a^{2}+ab+b^{2}}$.We know the algebraic identity $a^{3}-b^{3} = (a-b)(a^{2}+ab+b^{2})$.Therefore,the expression simplifies to $\frac{(a-b)(a^{2}+ab+b^{2})}{a^{2}+ab+b^{2}} = a-b$.Here,$a = 0.96$ and $b = 0.1$.Substituting these values,we get $a-b = 0.96 - 0.1 = 0.86$.