What is the simplified value of (2+1)(2^{2}+1 | vedclass

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(B) To simplify the expression $(2+1)(2^{2}+1)(2^{4}+1)(2^{8}+1)$,we use the algebraic identity $(a-b)(a+b) = a^{2}-b^{2}$.Multiply the expression by

Vedclass · Accepted Answer

$2^{16}-1$

Vedclass · Answer

(B) To simplify the expression $(2+1)(2^{2}+1)(2^{4}+1)(2^{8}+1)$,we use the algebraic identity $(a-b)(a+b) = a^{2}-b^{2}$.Multiply the expression by $(2-1)$,which is equal to $1$:$(2-1)(2+1)(2^{2}+1)(2^{4}+1)(2^{8}+1)$Using the identity repeatedly:$(2^{2}-1)(2^{2}+1)(2^{4}+1)(2^{8}+1)$$(2^{4}-1)(2^{4}+1)(2^{8}+1)$$(2^{8}-1)(2^{8}+1)$$= 2^{16}-1$Thus,the simplified value is $2^{16}-1$.

What is the simplified value of $(2+1)(2^{2}+1)(2^{4}+1)(2^{8}+1)?$

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