The value of frac{0.125+0.027}{0.5 times 0.5+ | vedclass

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(C) The given expression is $\frac{0.125+0.027}{0.5 	imes 0.5+0.09-0.15}$.We can write the numerator as $(0.5)^3 + (0.3)^3$ because $0.5^3 = 0.125$ a

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$0.8$

Vedclass · Answer

(C) The given expression is $\frac{0.125+0.027}{0.5 	imes 0.5+0.09-0.15}$.We can write the numerator as $(0.5)^3 + (0.3)^3$ because $0.5^3 = 0.125$ and $0.3^3 = 0.027$.We can write the denominator as $(0.5)^2 + (0.3)^2 - (0.5)(0.3)$ because $0.5^2 = 0.25$,$0.3^2 = 0.09$,and $(0.5)(0.3) = 0.15$.Using the algebraic identity $a^3 + b^3 = (a+b)(a^2 + b^2 - ab)$,where $a = 0.5$ and $b = 0.3$,the expression becomes:$\frac{(0.5+0.3)(0.5^2 + 0.3^2 - 0.5 	imes 0.3)}{0.5^2 + 0.3^2 - 0.5 	imes 0.3}$.Canceling the common term $(0.5^2 + 0.3^2 - 0.5 	imes 0.3)$,we get $0.5 + 0.3 = 0.8$.

The value of $\frac{0.125+0.027}{0.5 \times 0.5+0.09-0.15}$ is

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