The value of tan 56^{circ} - tan 11^{circ} - | vedclass

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(C) We know the formula for the tangent of a difference: $	an(A - B) = \frac{	an A - 	an B}{1 + 	an A 	an B}$.Let $A = 56^{\circ}$ and $B = 11^{\

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$1$

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(C) We know the formula for the tangent of a difference: $	an(A - B) = \frac{	an A - 	an B}{1 + 	an A 	an B}$.Let $A = 56^{\circ}$ and $B = 11^{\circ}$. Then $A - B = 45^{\circ}$.Substituting these values into the formula:$	an 45^{\circ} = \frac{	an 56^{\circ} - 	an 11^{\circ}}{1 + 	an 56^{\circ} 	an 11^{\circ}}$.Since $	an 45^{\circ} = 1$,we have:$1 = \frac{	an 56^{\circ} - 	an 11^{\circ}}{1 + 	an 56^{\circ} 	an 11^{\circ}}$.Multiplying both sides by $(1 + 	an 56^{\circ} 	an 11^{\circ})$:$1 + 	an 56^{\circ} 	an 11^{\circ} = 	an 56^{\circ} - 	an 11^{\circ}$.Rearranging the terms to match the expression in the question:$	an 56^{\circ} - 	an 11^{\circ} - 	an 56^{\circ} 	an 11^{\circ} = 1$.

The value of $\tan 56^{\circ} - \tan 11^{\circ} - \tan 56^{\circ} \tan 11^{\circ}$ is

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