The value of $2 \cot ^{-1} \frac{1}{2} - \cot ^{-1} \frac{4}{3}$ is

  • A
    $-\frac{\pi}{8}$
  • B
    $\frac{3 \pi}{2}$
  • C
    $\frac{\pi}{4}$
  • D
    $\frac{\pi}{2}$

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Solve for $x$: $\tan^{-1}\left(\frac{1-x}{1+x}\right) = \frac{1}{2} \tan^{-1} x$,where $x > 0$.

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