The value of int frac{sin x}{cos^2 x} , dx is | vedclass

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Question

(C) Given $I = \int \frac{\sin x}{\cos^2 x} \, dx$. We can rewrite the integral as $I = \int \frac{1}{\cos x} \cdot \frac{\sin x}{\cos x} \, dx = \int

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$\sec x + k$

Vedclass · Answer

(C) Given $I = \int \frac{\sin x}{\cos^2 x} \, dx$. We can rewrite the integral as $I = \int \frac{1}{\cos x} \cdot \frac{\sin x}{\cos x} \, dx = \int \sec x 	an x \, dx$. We know that the derivative of $\sec x$ is $\sec x 	an x$. Therefore,$\int \sec x 	an x \, dx = \sec x + k$,where $k$ is the constant of integration.

The value of $\int \frac{\sin x}{\cos^2 x} \, dx$ is

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