The value of $I_c$ for the configuration shown is in $mA$.

In a transistor, comparing the doping of emitter, base, and collector, the part which is heavily doped and that which is lightly doped are respectively:

$A$ transistor is connected in common emitter configuration. The collector supply is $8 V$ and the voltage drop across a resistor of $800 \Omega$ in the collector circuit is $0.5 V$. If the current gain factor $\alpha$ is $0.96$,the base current is

For a given transistor,if $\alpha = 0.95$,find the common emitter current gain $\beta$.

An $n-p-n$ transistor is connected in common-emitter configuration as shown in the figure. If the collector current is $5 \text{ mA}$,$V_{BE} = 0.6 \text{ V}$,$V_{CE} = 3 \text{ V}$,and the common-emitter current amplification factor $\beta = 50$,then the values of $R_1$ and $R_2$ are respectively.

In an $n-p-n$ transistor circuit,the collector current is $20 \, mA$. If $90 \%$ of the emitted electrons reach the collector,calculate the emitter current and base current.