The Van der Waals parameters for gases W,X,Y, | vedclass

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(D) The critical temperature $(T_c)$ of a gas is given by the formula: $T_c = \frac{8a}{27Rb}$.From the formula,$T_c$ is directly proportional to $a$

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$Z$

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(D) The critical temperature $(T_c)$ of a gas is given by the formula: $T_c = \frac{8a}{27Rb}$.From the formula,$T_c$ is directly proportional to $a$ and inversely proportional to $b$ $(T_c \propto \frac{a}{b})$.Calculating the ratio $\frac{a}{b}$ for each gas:For $W$: $\frac{4.0}{0.027} \approx 148.15$For $X$: $\frac{8.0}{0.030} \approx 266.67$For $Y$: $\frac{6.0}{0.032} = 187.5$For $Z$: $\frac{12.0}{0.027} \approx 444.44$Since gas $Z$ has the highest ratio of $\frac{a}{b}$,it has the highest critical temperature.

$Gas$	$a \ (atm \ L^2 \ mol^{-2})$	$b \ (L \ mol^{-1})$
$W$	$4.0$	$0.027$
$X$	$8.0$	$0.030$
$Y$	$6.0$	$0.032$
$Z$	$12.0$	$0.027$

The Van der Waals parameters for gases $W$,$X$,$Y$,and $Z$ are given below. Which one of these gases has the highest critical temperature?

$Gas$ $a \ (atm \ L^2 \ mol^{-2})$ $b \ (L \ mol^{-1})$

$W$ $4.0$ $0.027$

$X$ $8.0$ $0.030$

$Y$ $6.0$ $0.032$

$Z$ $12.0$ $0.027$

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The Van der Waals parameters for gases $W$,$X$,$Y$,and $Z$ are given below. Which one of these gases has the highest critical temperature? $Gas$ $a \ (atm \ L^2 \ mol^{-2})$ $b \ (L \ mol^{-1})$ $W$ $4.0$ $0.027$ $X$ $8.0$ $0.030$ $Y$ $6.0$ $0.032$ $Z$ $12.0$ $0.027$