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(D) The terminal potential difference $V$ of a cell is given by the equation: $V = E - Ir$,where $E$ is the $EMF$ and $r$ is the internal resistance.T

Vedclass · Accepted Answer

$3 	ext{ V}, 0.5 \ \Omega$

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(D) The terminal potential difference $V$ of a cell is given by the equation: $V = E - Ir$,where $E$ is the $EMF$ and $r$ is the internal resistance.This equation is in the form of a straight line $y = mx + c$,where $V$ is on the y-axis and $I$ is on the x-axis.$1$. When the current $I = 0$,the terminal potential difference $V = E$. From the graph,at $I = 0$,$V = 3 	ext{ V}$. Therefore,$E = 3 	ext{ V}$.$2$. When the terminal potential difference $V = 0$,the current is $I = 6 	ext{ A}$. Substituting these values into the equation: $0 = E - Ir \implies 0 = 3 - (6)r$.$3$. Solving for $r$: $6r = 3 \implies r = \frac{3}{6} = 0.5 \ \Omega$.Thus,the $EMF$ is $3 	ext{ V}$ and the internal resistance is $0.5 \ \Omega$.

The variation of terminal potential difference $(V)$ with current $(I)$ flowing through a cell is as shown in the graph. The $EMF$ $(E)$ and internal resistance $(r)$ of the cell are:

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