Medium
The velocity constant of a reaction is $K$. Which of the following statements is not true regarding $K$?
- A$K$ is a constant for a reaction at a given temperature.
- BThe value of $K$ changes when the temperature changes.
- C$K$ is the velocity of the reaction at unit concentrations of the reactant.
- D$K$ is a constant for all reactions.
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Similar Questions
........ of a reaction cannot be determined experimentally.
$t_{1/2} =$ constant confirms a first-order reaction. If $a^2 t_{1/2} =$ constant,it confirms that the order of the reaction is ($a =$ initial concentration of reactant).
Medium
View SolutionConsider the kinetic data given in the following table for the reaction $A + B + C \rightarrow$ Product.
Experiment No.
$[A] \ (mol \ dm^{-3})$
$[B] \ (mol \ dm^{-3})$
$[C] \ (mol \ dm^{-3})$
Rate of reaction $(mol \ dm^{-3} \ s^{-1})$
$1$
$0.2$
$0.1$
$0.1$
$6.0 \times 10^{-5}$
$2$
$0.2$
$0.2$
$0.1$
$6.0 \times 10^{-5}$
$3$
$0.2$
$0.1$
$0.2$
$1.2 \times 10^{-4}$
$4$
$0.3$
$0.1$
$0.1$
$9.0 \times 10^{-5}$
The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .
| Experiment No. | $[A] \ (mol \ dm^{-3})$ | $[B] \ (mol \ dm^{-3})$ | $[C] \ (mol \ dm^{-3})$ | Rate of reaction $(mol \ dm^{-3} \ s^{-1})$ |
| $1$ | $0.2$ | $0.1$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $2$ | $0.2$ | $0.2$ | $0.1$ | $6.0 \times 10^{-5}$ |
| $3$ | $0.2$ | $0.1$ | $0.2$ | $1.2 \times 10^{-4}$ |
| $4$ | $0.3$ | $0.1$ | $0.1$ | $9.0 \times 10^{-5}$ |
The rate of the reaction for $[A]=0.15 \ mol \ dm^{-3}, [B]=0.25 \ mol \ dm^{-3}$ and $[C]=0.15 \ mol \ dm^{-3}$ is found to be $Y \times 10^{-5} \ mol \ dm^{-3} \ s^{-1}$. The value of $Y$ is . . . . . .
MediumIIT 2019
View SolutionFor the reaction $A + B \rightarrow \text{Product}$,the order with respect to $A$ is $1$ and with respect to $B$ is $1/2$. When the concentrations of both $A$ and $B$ are increased by a factor of $4$,the rate of reaction increases by a factor of .......
Medium
View Solution$A$ complex reaction takes place in the following steps:
$NO_2Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{(g)}$ (slow)
$NO_2Cl_{(g)} + Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{2(g)}$ (fast)
Identify the rate law equation for this reaction.
$NO_2Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{(g)}$ (slow)
$NO_2Cl_{(g)} + Cl_{(g)} \longrightarrow NO_{2(g)} + Cl_{2(g)}$ (fast)
Identify the rate law equation for this reaction.
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