(A) Let $V \ L$ of $10 \ N$ $HCl$ be mixed with $(1-V) \ L$ of $4 \ N$ $HCl$ to obtain $1 \ L$ of $7 \ N$ $HCl$.Using the mixture formula $N_1 V_1 + N

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$0.50 \ L$ of $10 \ N$ $HCl$ and $0.50 \ L$ of $4 \ N$ $HCl$

(A) Let $V \ L$ of $10 \ N$ $HCl$ be mixed with $(1-V) \ L$ of $4 \ N$ $HCl$ to obtain $1 \ L$ of $7 \ N$ $HCl$.Using the mixture formula $N_1 V_1 + N_2 V_2 = N_3 V_3$:$10V + 4(1-V) = 7 \times 1$$10V + 4 - 4V = 7$$6V = 3$$V = 0.50 \ L$Thus,the volume of $10 \ N$ $HCl$ is $0.50 \ L$ and the volume of $4 \ N$ $HCl$ is $1 - 0.50 = 0.50 \ L$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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The volume of $10 \ N$ and $4 \ N$ $HCl$ required to make $1 \ L$ of $7 \ N$ $HCl$ are

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A
$0.50 \ L$ of $10 \ N$ $HCl$ and $0.50 \ L$ of $4 \ N$ $HCl$
B
$0.60 \ L$ of $10 \ N$ $HCl$ and $0.40 \ L$ of $4 \ N$ $HCl$
C
$0.80 \ L$ of $10 \ N$ $HCl$ and $0.20 \ L$ of $4 \ N$ $HCl$
D
$0.75 \ L$ of $10 \ N$ $HCl$ and $0.25 \ L$ of $4 \ N$ $HCl$

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The volume of $10 \ N$ and $4 \ N$ $HCl$ required to make $1 \ L$ of $7 \ N$ $HCl$ are

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If the mole fraction of $H_2SO_4$ in an aqueous solution of $H_2SO_4$ is $0.1$,then the molality of the solution is ........... $m$.

The molarity of the solution obtained by mixing $800 \ mL$ of $0.5 \ M$ $HCl$ and $200 \ mL$ of $1 \ M$ $HCl$ will be ....... $M$.

Concentration terms such as mass percentage,$ppm$,mole fraction,and molality are independent of temperature,whereas molarity is a function of temperature. Explain.

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