The volume of gas $A$ is twice that of gas $B$. The compressibility factor of gas $A$ is thrice that of gas $B$ at the same temperature. The ratio of the pressures of the gases for equal number of moles is:

  • A
    $3P_A = 2P_B$
  • B
    $2P_A = 3P_B$
  • C
    $P_A = 3P_B$
  • D
    $P_A = 2P_B$

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Similar Questions

Explain the compressibility factor $(Z)$.

At $300 \ K$,one mole of a gas present in a $10 \ L$ flask exerted a pressure of $2.706 \ atm$. What is its compressibility factor $(Z)$? (Given $R=0.082 \ L \ atm \ mol^{-1} \ K^{-1}$).

$1 \ mol$ of a real gas is kept at a high pressure of $100 \ bar$ at $300 \ K$. If the van der Waals constant $b$ is $0.005 \ L \ mol^{-1}$, what are the values of the compressibility factor $Z$ of the gas and the $\%$ deviation of volume from ideality?
$Z$$\%$ Deviation

The term that corrects for the attractive forces present in a real gas in the van der Waals equation is

At low pressure,the van der Waals equation becomes

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